I have created a more general function, that sorts more than two lists based on another one, inspired by @Whatang's answer. There are at least two good idioms for this problem. Does a summoned creature play immediately after being summoned by a ready action? It would be preferable instead to have a method sortCompetitors(), that would sort the list, without leaking it: and remove completely the method getCompetitors(). Theoretically Correct vs Practical Notation, Bulk update symbol size units from mm to map units in rule-based symbology. http://scienceoss.com/sort-one-list-by-another-list/. 1. more_itertools has a tool for sorting iterables in parallel: I actually came here looking to sort a list by a list where the values matched. The returned comparable is serializable. Working on improving health and education, reducing inequality, and spurring economic growth? This is quite inefficient, though, and you should probably create a Map from listA to lookup the positions of the items faster. The nature of simulating nature: A Q&A with IBM Quantum researcher Dr. Jamie We've added a "Necessary cookies only" option to the cookie consent popup. It only takes a minute to sign up. All of the values at the end of the list will be in their order dictated by the list2. Browse other questions tagged, Where developers & technologists share private knowledge with coworkers, Reach developers & technologists worldwide. Connect and share knowledge within a single location that is structured and easy to search. Like Tim Herold wrote, if the object references should be the same, you can just copy listB to listA, either: Or this if you don't want to change the List that listA refers to: If the references are not the same but there is some equivalence relationship between objects in listA and listB, you could sort listA using a custom Comparator that finds the object in listB and uses its index in listB as the sort key. you can leverage that solution directly in your existing df. We first get the String values in a list. Examples: Input: words = {"hello", "geeksforgeeks"}, order = "hlabcdefgijkmnopqrstuvwxyz" Output: "hello", "geeksforgeeks" Explanation: All rights reserved. The most obvious solution to me is to use the key keyword arg. What do you mean when you say that you're unable to persist the order "on the backend"? [Solved] Sorting a list based on another list's values - Java
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